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If human space vacation is limited through the G force vulnerability, is there a means to counter G forces? 26

How you can go about calculating the size and Electrical power requirements for an area-based linear accelerator or railgun to speed up smaller probes? five

With the stationary observer's viewpoint the traveler's fee of acceleration would slow because they approached the speed of sunshine. The traveler would see no transform among their velocity plus the velocity of light. Instead they would knowledge time at an significantly slower charge which would successfully induce the gap to your spot to be shorter.

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James JenkinsJames Jenkins 27.2k2323 gold badges108108 silver badges242242 bronze badges $endgroup$ three 4 $begingroup$ "1g of thrust" pointed straight up will equilibrium gravity, and result in you floating. "1g" (as I study it), would be the acceleration because of the Earth's gravity; if that's how you truly determine it, then your acceleration decreases as you obtain more (and 'really feel less pull') from Earth.

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seventy six c and the passengers perceiving 300 times. I am not sure which is accurate, I am not comfy with Particular relativity. I do not Believe possibly an out of doors notice nor the accelerating passengers would see what seems to generally be a Newtonian universe. $endgroup$

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$begingroup$ When you've got the Vitality for a constant 1G thrust, just how long would it not acquire to have towards the planets within our solar program? Just how long with the five nearest photo voltaic systems?

But that time is from your viewpoint of stationary observers within the departure point. The excursion's duration from the traveler's viewpoint could be a lot less because of the time dilation outcome predicted by Einstein's Principle of Relativity. The higher the gap, the greater the pace within the stationary observer's viewpoint.

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1 $begingroup$ @Mark not really true. In fact, in case you notice things falling in continual gravity, you still cannot see them transcend speed of sunshine, this means that Newtonian physics won't hold whilst viewed via the ship. $endgroup$

HopDavidHopDavid 16k4444 silver badges8080 bronze badges $endgroup$ nine twenty $begingroup$ Your "insert a bit more than the usual yr for every lightyear distance" is correct for an out of doors observer, but for somebody aboard the ship, the Newtonian product is proper for all distances (as calculated before starting acceleration): Lorentz contraction will shrink the universe throughout travel to give the looks of Newtonian physics. $endgroup$

As a result of time dilation influence, 1G acceleration needs to be sufficient to travel anywhere in our galaxy in a lot less than a lifetime from your viewpoint of your traveler, although not the stationary observer. For more info on some time dilation effect read Stephen Hawking's "Transient Historical past of your time"

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